College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 97: 26

Answer

a). $14.4N$ in +y-direction b). $(1.1)x+(12.64)y$

Work Step by Step

a). The horizontal components of $F_{1}$ and $F_{2}$ balance each other, since they are in opposite direction and exactly equal. So, net resultant force = $2\times 12.0N\times sin37^{\circ}=14.4N$ in positive y-direction. b). Resultant force =$(12cos27^{\circ}-12cos37^{\circ})x+(12sin27^{\circ}+12sin37^{\circ})y$ =$(1.1)x+(12.64)y$
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