Answer
a). $v_{x}=32.9m/s$
$v_{y}=6.1m/s$
b). Magnitude of average velocity $=33.5m/s$
Angle = $\theta=10.5^{\circ}$ with respect to horizontal.
c). We cannot calculate the average speed, because we do not know its exact path, hence we do not know the distance covered.
Work Step by Step
a). $v_{x}=\frac{135}{4.1}=32.9m/s$
$v_{y}=\frac{25}{4.1}=6.1m/s$
b). Magnitude of average velocity $=\frac{\sqrt( 25^{2}+135^{2})}{4.1}=33.5m/s$
Angle = $\theta=tan^{-1} (\frac{25}{135})=10.5^{\circ}$
c). We cannot calculate the average speed, because we do not know its exact path, hence we do not know the distance covered.
