College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 97: 20

Answer

$Vec(x_{1})=(20m)x$ $Vec(x_{2})=(15m)x$ So, a). $vec(x_{1})+vec(x_{2})=(35m)x,$ b). $vec(x_{1})-vec(x_{2})=(5m)x,$ c). $vec(x_{2})-vec(x_{1})=(-5m)x.$ Graph is shown.

Work Step by Step

$Vec(x_{1})=(20m)x$ $Vec(x_{2})=(15m)x$ So, a). $vec(x_{1})+vec(x_{2})=(35m)x,$ b). $vec(x_{1})-vec(x_{2})=(5m)x,$ c). $vec(x_{2})-vec(x_{1})=(-5m)x.$ Graph is shown.
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