Answer
$Vec(x_{1})=(20m)x$
$Vec(x_{2})=(15m)x$
So, a). $vec(x_{1})+vec(x_{2})=(35m)x,$
b). $vec(x_{1})-vec(x_{2})=(5m)x,$
c). $vec(x_{2})-vec(x_{1})=(-5m)x.$
Graph is shown.
Work Step by Step
$Vec(x_{1})=(20m)x$
$Vec(x_{2})=(15m)x$
So, a). $vec(x_{1})+vec(x_{2})=(35m)x,$
b). $vec(x_{1})-vec(x_{2})=(5m)x,$
c). $vec(x_{2})-vec(x_{1})=(-5m)x.$
Graph is shown.