College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 97: 18

Answer

As per dot product of 2 vectors A and B, with angle $\theta$ between them , $vec(A) vec(B) = |vec(A)|\times|vec(B)|\times cos\theta=vecA_{x}vecB_{x}+vecA_{y}vecB_{y}=0$ because , $cos\theta=0$ as $\theta=90^{\circ}$.

Work Step by Step

As per dot product of 2 vectors A and B, with angle $\theta$ between them , $vec(A) vec(B) = |vec(A)|\times|vec(B)|\times cos\theta=vecA_{x}vecB_{x}+vecA_{y}vecB_{y}=0$ because , $cos\theta=0$ as $\theta=90^{\circ}$.
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