Answer
$0.0638$
Work Step by Step
$a=\frac{v^{2}-u^{2}}{2S}$
Also, $F=coefficient\,of\,friction\times mg=ma$
Therefore, $Coefficient of friction=\frac{a}{g}=\frac{v^{2}-u^{2}}{2gS}=\frac{25}{2\times20\times9.8}=0.0638$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 139: 68
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