College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 139: 71

Answer

$0.77m$

Work Step by Step

$S=\frac{v^{2}-u^{2}}{2a}$ Also, $F=-coefficient\, of \,friction \times mg=ma$ a= $-coefficient \,of\, friction \times g$ Therefore, $S=\frac{0^{2}-3^{2}}{2\times0.6\times9.8}=0.77m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.