Answer
a). $45J$
b). $21.21m/s$
Work Step by Step
a). Final KE should be equal to work done which is equal to $F\times S=75N\times0.6m=45J$
b). So, $\frac{1}{2}\times mv^{2}=45J$
$v=\sqrt \frac{90}{0.2}=21.21m/s$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 5 - Work and Energy - Learning Path Questions and Exercises - Exercises - Page 176: 31
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