College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 5 - Work and Energy - Learning Path Questions and Exercises - Exercises - Page 176: 39

Answer

$5.64J$

Work Step by Step

Let us assume that the weight acts at the center of the book i.e. 2 cm=0.02m from base. Work needed to stack all 6 books one after another $=mg\times(0.02+0.06+0.10+0.14+0.18+0.22)=0.8\times9.8\times0.72=5.64J$
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