Answer
710 kg.
Work Step by Step
Use the density of gold (Table 10–1) and calculate the volume. Round to two significant figures.
$$M=\rho V = (19.3 \times 10^3 kg/m^3)(0.54m)(0.31m)(0.22m) \approx 710 kg$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 10 - Fluids - Problems - Page 285: 3
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