Answer
$0.070 m^3$
Work Step by Step
Assume that the density of a human body is approximately that of water. Use a mass of 70 kg.
$$V=\frac{m}{\rho}=\frac{70 kg}{1.00 \times 10^3 kg/m^3}=0.070 m^3$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 10 - Fluids - Problems - Page 285: 4
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