Answer
$1.7\times10^{13}J/h$.
Work Step by Step
Find the maximum/Carnot efficiency using equation 15–5. Temperatures are in kelvins.
$$e=1-\frac{T_L}{T_H}=1-\frac{330+273}{660+273}=0.3537$$
Electric energy is generated at a rate of 1.4 GW, with an operating efficiency of 0.65. Find the total power P generated.
$$1.4GW=P(0.3537)(0.65)$$
$$P=6.089GW$$
Heat is therefore exhausted at a rate of 6.089GW – 1.4 GW = 4.689 GW.
Convert to find the exhaust heat discharged per hour.
$$(4.689\times10^9 J/s)(3600s/h)\approx1.7\times10^{13}J/h$$.
