Answer
$1.8\times10^3W$
Work Step by Step
The maximum efficiency (Carnot efficiency) is given by equation 15–5. Make sure to measure temperatures in kelvins.
$$e_{ideal}=1-\frac{T_L}{T_H}=1-\frac{(45+273)K}{(210+273)K}=0.3416$$
Next, use the definition of the efficiency of a heat engine.
$$e=\frac{W}{Q_H}=\frac{W}{W+Q_L}$$
$$Q_L=W(\frac{1}{e}-1)$$
$$\frac{ Q_L }{t} =\frac{W}{t}(\frac{1}{e}-1)$$
$$\frac{ Q_L }{t} =(910watts)(\frac{1}{0.3416}-1)$$
$$\frac{ Q_L }{t} =1754watts\approx1.8\times10^3W$$
