Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 11 - Refrigeration Cycles - Problems - Page 648: 11-98

Answer

$\mathrm{COP}_{\mathrm{R}}=1200 W$

Work Step by Step

The required power input is determined from the definition of $\mathrm{COP}_{\mathrm{R}}$, $$ \mathrm{COP}_{\mathrm{R}}=\frac{\dot{Q}_L}{\dot{W}_{\text {in }}} \longrightarrow \dot{W}_{\text {in }}=\frac{\dot{Q}_L}{\mathrm{COP}_{\mathrm{R}}}=\frac{180 \mathrm{~W}}{0.15}=1200 \mathrm{~W} $$
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