Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 12 - Thermodynamic Property Relations - Problems - Page 682: 12-46

Answer

See explanation

Work Step by Step

The definition for the isothermal compressibility is $$ \alpha=-\frac{1}{v}\left(\frac{\partial v}{\partial P}\right)_T $$ The derivative is $$ \left(\frac{\partial P}{\partial v}\right)_T=-\frac{R T}{(\boldsymbol{v}-b)^2}+\frac{a}{T^{1 / 2}} \frac{2 \boldsymbol{v}+b}{\boldsymbol{v}^2(\boldsymbol{v}+b)^2} $$ Substituting, $$ \alpha=-\frac{1}{v}\left(\frac{\partial \boldsymbol{v}}{\partial P}\right)_T=-\frac{1}{\boldsymbol{v}}\left(\frac{1}{-\frac{R T}{(\boldsymbol{v}-b)^2}+\frac{a}{T^{1 / 2}} \frac{2 \boldsymbol{v}+b}{\boldsymbol{v}^2(\boldsymbol{v}+b)^2}}\right)=-\frac{1}{-\frac{R T \boldsymbol{v}}{(\boldsymbol{v}-b)^2}+\frac{a}{T^{1 / 2}} \frac{2 \boldsymbol{v}+b}{(\boldsymbol{v}+b)^2}} $$
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