Answer
$\dot{W}_{\mathrm{rev}}=2300 \mathrm{~kW}
$
Work Step by Step
From the definition of the second law efficiency $$
\eta_{\mathrm{II}}=\frac{\dot{W}_{\mathrm{rev}}}{\dot{W}_{\text {actual }}} \rightarrow 0.20=\frac{\dot{W}_{\mathrm{rev}}}{11,500 \mathrm{~kW}} \rightarrow \dot{W}_{\mathrm{rev}}=2300 \mathrm{~kW}
$$ which is the maximum power that can be generated.
