Answer
$T^{}= 570$ K
$P= 957$ kPa
Work Step by Step
The inlet temperature and pressure in this case is equivalent to the stagnation temperature and pressure since the inlet velocity of the carbon dioxide is said to be negligible. That is,
$T_0=T_{\mathrm{i}}=400 \mathrm{~K}$ and $P_0=P_{\mathrm{i}}=1200 \mathrm{kPa}$. Then, $$
T=T_0\left(\frac{2}{2+(k-1) \mathrm{Ma}^2}\right)=(600 \mathrm{~K})\left(\frac{2}{2+(1.288-1)(0.6)^2}\right)=570.43 \mathrm{~K} \cong 570 \mathrm{~K}
$$ and $$
P=P_0\left(\frac{T}{T_0}\right)^{k /(k-1)}=(1200 \mathrm{kPa})\left(\frac{570.43 \mathrm{~K}}{600 \mathrm{~K}}\right)^{1.288 /(1.288-1)}=957.23 \mathrm{~K} \cong 957 \mathbf{k P a}
$$
