Answer
Here is the proof. We have to prove that sum of two odd integers is even.
Work Step by Step
SOLUTION:
Let,
First odd integer (a) = 2k+1
&
Second odd integer (b) = 2m+1
where in both. k and m are the any integers.
Now,
a + b should be even i.e multiple of 2.
So,
a + b = (2k+1) + (2m+1)
=2k +2m +2 = 2(k+m+1) = even.
REASON:
As,
k & m are integers and (k+m+1) is the multiple of 2 which shows it is even number.
Hence,
Proved.
