Answer
See explanation below.
Work Step by Step
x is considered rational and y is considered irrational.
x^y = 2^$\sqrt 2$ = which is irrational, therefore it is proven.
Discrete Mathematics and Its Applications, Seventh Edition
by Rosen, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0073383090
ISBN 13:
978-0-07338-309-5
Chapter 1 - Section 1.8 - Proof Methods and Strategy - Exercises - Page 108: 13
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