Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter R - Section R.2 - Fractions - Exercise Set - Page R-16: 67

Answer

$48 \frac{1}{15}$

Work Step by Step

$ 17 \frac{2}{5} + 30 \frac{2}{3} = \frac{87}{5} + \frac{92}{3} = \frac{87*3}{5*3} + \frac{92*5}{3*5} = \frac{261}{15} + \frac{460}{15} = \frac{721}{15} = 48 \frac{1}{15}$
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