Answer
$(x+4)^2+(y-5)^2=4$
Work Step by Step
The standard form of a circle with center at $(h,k)$ and radius $r$ is:
$$(x-h)^2+(y-k)^2=r^2$$
Substituting $h=-4$, $k=5$ and $r=2$:
$$[x-(-4)]^2+(y-5)^2=2^2$$ Simplifying:
$$(x+4)^2+(y-5)^2=4$$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.1 - Graphs of Equations - 1.1 Exercises - Page 79: 61
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