Answer
True
Since $f(x)=0$ has no real solutions the graph of $f(x)$ has no x-intercepts.
Work Step by Step
$f(x)=0$
$-12x^2-1=0$
$-12x^2=1$
$x^2=-\frac{1}{12}$
It has no real solution.
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 3 - 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 250: 75
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