Answer
$2012$
Work Step by Step
The vertex lies in the symmetry axis of the parabola. So, if $P(t_1)=P(t_2)$, in which $t_1\ne t_2$, then $t_1$ and $t_2$ are equidistant from the $t$ of the vertex.
$\frac{2008+2016}{2}=2012$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 3 - 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 250: 80c
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