Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.1 - Solving Simple Equations - Exercises - Page 9: 32

Answer

$b=\frac{1}{2}$

Work Step by Step

Use the Addition Property of Equality by adding $\frac{3}{16}$ from each side of the equation: $$\begin{align*} b-\frac{3}{16}+\frac{3}{16}&=\frac{5}{16}+\frac{3}{16}\\ b&=\frac{8}{16}\\\ b&=\frac{1}{2}\end{align*}$$ Check the solution by substituting $\frac{1}{2}$ to the variable in the given equation: $$\begin{align*} b-\frac{3}{16}&=\frac{5}{16}\\ \frac{1}{2}-\frac{3}{16}&\stackrel{?}{=}\frac{5}{16}\\ \frac{8}{16}-\frac{3}{16}&\stackrel{?}{=}\frac{5}{16}\\ \frac{5}{16}&\stackrel{\checkmark}{=}\frac{5}{16}\end{align*}$$ Thus, the solution is $b=\frac{1}{2}$.
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