Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.2 - Solving Multi-Step Equations - Exercises - Page 16: 18

Answer

$g=-3$

Work Step by Step

$$\begin{align*} \frac{-2(4g-3)}{-2}&=\frac{30}{-2} &\text{Divide -2 to both sides..}\\ 4g-3&=-15 &\text{Simplify.}\\ 4g-3+3&=-15+3 &\text{Add 3 to both sides.}\\ 4g&=-12 &\text{Simplify.}\\ \frac{4g}{4}&=\frac{-12}{4} &\text{Divide 4 to both sides.}\\ g&=-3&\text{Simplify.} \end{align*}$$ Check the answer by substituting $-3$ to the variable in the given equation. $$\begin{align*} -2(4g-3)&=30\\ -2(4\cdot(-3)-3)&\stackrel{?}{=}30\\ -2(-15)&\stackrel{?}{=}30\\ 30&\stackrel{\checkmark}{=}30 \end{align*}$$ Thus, the solution is $g=-3$.
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