Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.2 - Solving Multi-Step Equations - Exercises - Page 16: 21

Answer

$c=5$

Work Step by Step

$$\begin{align*} 27&=3c-3(6)-(-3)(2c) &\text{Apply the Distributive Property}\\ 27&=3c-18+6c &\text{Simplify.}\\ 27&=9c-18 &\text{Combine like terms.}\\ 27+18&=9c-18+18 &\text{Add 18 to both sides.}\\ 45&=9c &\text{Simplify.}\\ \frac{45}{9}&=\frac{9c}{9} &\text{Divide 9to both sides.}\\ 5&=c&\text{Simplify.} \end{align*}$$ Check the answer by substituting $5$ to the variable in the given equation. $$\begin{align*} 27&=3c-3(6-2c)\\ 27&\stackrel{?}{=}3(5)-3(6-2\cdot5)\\ 27&\stackrel{?}{=}15+12\\ 27&\stackrel{\checkmark}{=}27 \end{align*}$$ Thus, the solution is $c=5$.
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