Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.2 - Solving Multi-Step Equations - Exercises - Page 17: 42

Answer

The width of the court is $36\; feet$. The length of the court is $78\;feet$.

Work Step by Step

The given perimeter of the tennis court is $228\;feet$. Length of the court is $2w+6$. Width of the court is $w$. Perimeter of the court is $P=2($length $+$ width$)$ Substitute all the values. $\Rightarrow 228=2(2w+6+w)$ Add like terms. $\Rightarrow 228=2(3w+6)$ Use distributive property. $\Rightarrow 228=6w+12$ Subtract $12$ from each side. $\Rightarrow 228-12=6w+12-12$ Simplify. $\Rightarrow 216=6w$ Divide each side by $6$. $\Rightarrow 36=w$ Length of the court is $2w+6=2(36)+6=72+6=78$ Hence, the width of the court is $36\; feet$ and the length of the court is $78\;feet$.
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