College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.1 - Linear Equations - 1.1 Assess Your Understanding - Page 91: 73

Answer

$x =\dfrac{abc}{b+a}$

Work Step by Step

Multiply $ab$ to both sides of the equation to obtain: $\begin{array}{ccc} \require{cancel} &ab\left(\dfrac{x}{a} + \dfrac{x}{b}\right)&=&c(ab) \\&\cancel{a}b\left(\dfrac{x}{\cancel{a}}\right) + a\cancel{b}\left(\dfrac{x}{\cancel{b}}\right)&=&abc \\&bx+ax&=&abc \end{array}$ Factor out $x$ to obtain: $(b+a)x=abc$ Divide $(b+a)$ to both sides of the equation to obtain: $x =\dfrac{abc}{b+a}$
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