College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.2 - Quadratic Equations - 1.2 Assess Your Understanding - Page 101: 33

Answer

The solution is $\left\{-1, 3\right\}$.

Work Step by Step

Take the square root of both sides to obtain: $x-1 = \pm \sqrt{4} \\x-1= \pm \sqrt{2^2} \\x-1 = \pm 2$ Add 1 to both sides to obtain: $x = 1 \pm 2$ Split the solutions to obtain: $x_1 = 1+2 = 3 \\x_2 = 1-2 = -1$ Thus, the solution is $\left\{-1, 3\right\}$.
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