College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.1 - Real Numbers - R.1 Assess Your Understanding - Page 16: 76

Answer

$\dfrac{151}{18}$

Work Step by Step

Make the fractions similar using their LCD of 18 to obtain: $=\dfrac{8(2)}{9(2)} + \dfrac{15(9)}{2(9)} \\=\dfrac{16}{18}+\dfrac{135}{18} \\=\dfrac{16+135}{18} \\=\dfrac{151}{18}$
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