Answer
$3$
Work Step by Step
RECALL:
For a positive real number $a$:
$\sqrt{a^2}=a$
Substitute $2$ in for $x$ and $1$ in for $y$ to obtain:
$=\sqrt{2^2}+\sqrt{1^2}$
Use the rule above to obtain:
$=2+1
\\=3$
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