College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.3 - Geometry Essentials - R.3 Assess Your Understanding - Page 37: 43

Answer

$x=4$ $A=60^o \\B=90^o \\C=30^o$

Work Step by Step

RECALL: Two similar triangles have: (1) corresponding angles that are congruent; and (2) sides that are proportional Since corresponding angles are congruent, then $A=60^o \\B=90^o \\C=30^o$ Corresponding sides of similar triangles are proportional. Thus, $\dfrac{8}{4}=\dfrac{x}{2}$ Cross-multiply to obtain: $\begin{array}{ccc} &4(x) &= &8(2) \\&4x &= &16 \\&\frac{4x}{4} &= &\frac{16}{4} \\&x &= &4\end{array}$
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