Answer
The given expression is a polynomial whose degree is 0.
Work Step by Step
Using the rule $x^0=1$, the given expression is equivalent to:
$=5(1)
\\=5(x^0)
\\=5x^0$
The exponent of the variable is $0$, which is a nonnegative integer.
Thus, the given expression is a monomial and is consequently a polynomial.
The degree of a nonzero polynomial in one variable is equal to the exponent of the variable.
Thus, the degree of the polynomial is 0.
