Answer
$A'=\{2,6,9,10\}$
Work Step by Step
$\bf{\text{Solution Outline:}}$
To get the elements of $
A'
,$ remove all the elements of $A$ from $U.$
$\bf{\text{Solution Details:}}$
The complement of $A,$ given by $A'$, are all the elements of $U$ that are not in $A.$ By removing all the elements of $
A=\{1,3,4,5,7,8\}
$ from $
U=\{1,2,3,4,5,6,7,8,9,10\}
,$ then
\begin{array}{l}\require{cancel}
A'=\{2,6,9,10\}
.\end{array}
