College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Review Exercises - Page 74: 15

Answer

$B\cap E=\emptyset$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To get the elements of $ B\cap E ,$ get all the common elements of $B$ and $E$. $\bf{\text{Solution Details:}}$ The intersection of $B$ and $E,$ given by $B\cap E$, is the set that contains all the common elements of $B$ and $E$. With $ B=\{2,4,6,8 \} $ and $ E=\{3,7\} $ then \begin{array}{l}\require{cancel} B\cap E=\emptyset .\end{array}
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