College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Review Exercises - Page 75: 51

Answer

$-13$

Work Step by Step

Substituting $a=-1$, $b=-2$, and $c=4$, the given expression, $ \dfrac{9a+2b}{a+b+c} ,$ evaluates to \begin{array}{l}\require{cancel} \dfrac{9(-1)+2(-2)}{(-1)+(-2)+4} \\\\= \dfrac{-9-4}{-1-2+4} \\\\= \dfrac{-13}{1} \\\\= -13 .\end{array}
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