College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.3 - Polynomials - R.3 Exercises - Page 28: 18

Answer

$\frac{p^{8}}{q^{2}}$

Work Step by Step

$(\frac{p^{4}}{q})^{2}$ = $\frac{(p^{4})^{2}}{q^{2}}$ = $\frac{p^{4*2}}{q^{2}}$ = $\frac{p^{8}}{q^{2}}$
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