Answer
$\frac{-125n^{12}}{r^{6}}$
Work Step by Step
$(\frac{-5n^{4}}{r^{2}})^{3}$ = $\frac{(-5n^{4})^{3}}{(r^{2})^{3}}$ = $\frac{(-5)^{3}n^{4*3}}{r^{2*3}}$ = $\frac{-125n^{12}}{r^{6}}$
College Algebra (11th Edition)
by Lial, Margaret L.; Hornsby John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671791
ISBN 13:
978-0-32167-179-0
Chapter R - Section R.3 - Polynomials - R.3 Exercises - Page 28: 20
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