College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.3 - Polynomials - R.3 Exercises - Page 30: 98

Answer

$5,041$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To simplify the given expression, $ 71^2 ,$ use the special product for the square of a binomial. $\bf{\text{Solution Details:}}$ Since $71$ is near the number $70$ (a number that is convenient to operate with because of the zero), the given expression can be expressed as $ (70+1)^2 .$ Using the square of a binomial which is given by $(a+b)^2=a^2+2ab+b^2$ or by $(a-b)^2=a^2-2ab+b^2,$ then $(70+1)^2$ is equivalent to \begin{array}{l}\require{cancel} (70)^2+2(70)(1)+(1)^2 \\\\= 4900^2+140+1 \\\\= 5,041 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.