Answer
$-\frac{\sqrt[4]{3}}{2}$
Work Step by Step
Apply the rule: $\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$
$-\sqrt[4]{\frac{3}{16}}=-\frac{\sqrt[4]{3}}{\sqrt[4]{16}}$
Evaluate and simplify.
$-\sqrt[4]{\frac{3}{16}}=-\frac{\sqrt[4]{3}}{2}$
