College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Test - Page 77: 10

Answer

$36r^2-60r+25$

Work Step by Step

Using $(a\pm b)^2=a^2\pm2ab+b^2$ or the square of a binomial, the given expression, $ (6r-5)^2 ,$ is equivalent to \begin{array}{l}\require{cancel} (6r)^2-2(6r)(5)+(5)^2 \\\\= 36r^2-60r+25 .\end{array}
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