College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Test - Page 77: 9

Answer

$11x^2-x+2$

Work Step by Step

Distribute $3x$: to obtain: $(x^2-3x+2)-(x-4x^2)+3x(2x+1)$ $=x^2-3x+2-x+4x^2+3x\cdot2x+3x\cdot1$ $=x^2-3x+2-x+4x^2+6x^2+3x$ Combine like terms to otbain: $=x^2+4x^2+6x^2-3x-x+3x+2$ $=11x^2-x+2$
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