College Algebra (6th Edition)

by Blitzer, Robert F.

Published by Pearson

ISBN 10: 0-32178-228-3

ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.3 - Page 258: 113

Answer

See below.

Work Step by Step

Let the equation be $ax+by-12=0$ The x-intercept is at $y=0$, so then: $a(-2)-12=0$, thus $a=-6$. The y-intercept is at $x=0$, so then: $4b-12=0$, thus $b=3$.

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