Answer
$5$
Work Step by Step
If $f(x)=x^2$ and $x_1=1,x_2=4$, then $\frac{f(x_2)-f(x_1)}{x_2-x_1}=\frac{x_2^2-x_1^2}{x_2-x_1}=\frac{4^2-1^2}{4-1}=\frac{16-1}{3}=\frac{15}{3}=5$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 2 - Functions and Graphs - Exercise Set 2.3 - Page 258: 120
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