College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.2 - Page 33: 42

Answer

$=-\frac{216}{y^{3}}$

Work Step by Step

When a quotient is raised to a power, raise both the numerator and the denominator to that power: $$(-\frac{6}{y})^{3}$$ $$=\frac{(-6)^{3}}{y^{3}}$$ $$=\frac{-216}{y^{3}}$$ $$=-\frac{216}{y^{3}}$$
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