Answer
$-(x+5)(x-1)$
Work Step by Step
$-x^{2}-4x+5$
We can write it as
$-(x^{2}+4x-5)$
Since the last term of $-(x^{2}+4x-5)$ is -5. We need to find two factors of -5 that have a sum of 4.
5 and -1 are factors of -5. Also, $5\times-1=-5$ and $5-1=4$
Therefore, $-(x^{2}+4x-5)$ can be written as
$-(x^{2}+5x-x-5)$
Factor out common factors.
$=-(x(x+5)-1(x+5))$
Factor out common factor $(x+5)$
$=-((x+5)(x-1))$
$-x^{2}-4x+5=-(x+5)(x-1)$$
