College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Mid-Chapter Check Point - Page 63: 16

Answer

$-\frac{12y^{15}}{x^3}$

Work Step by Step

Simplify by dividing the exponents in the denominator. Do this by subtracting the exponents. Then make sure to put terms with negative exponents in the denominator. $\frac{24x^2y^{13}}{-2x^5y^{-2}}$ $-12x^{2-5}y^{13-(-2)}$ $-12x^{-3}y^{15}$ $-\frac{12y^{15}}{x^3}$
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