College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Mid-Chapter Check Point - Page 63: 19

Answer

$1.2$ x $10^{-2}$

Work Step by Step

Divide the number normally, and then divide the exponents by subtracting the exponents to simplify. Then place the decimal point after the ones place and write the proper exponent. $\frac{24*10^3}{2*10^6}$ $12$ x $10^{3-6}$ $12$ x $10^{-3}$ $1.2$ x $10^{-2}$
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