Answer
True.
Work Step by Step
True because we can get the eigenvalues by solving the equation of the characteristic polynomial being equal to $0$. Thus the equations are the same, thus the eigenvalues will be the same as well.
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 7 - Eigenvalues and Eigenvectors - 7.1 The Eigenvalue/Eigenvector Problem - True-False Review - Page 443: c
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