Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.4 Positive and Negative Real Numbers - 1.4 Exercise Set - Page 36: 94

Answer

$0.9\overline{9}=1$

Work Step by Step

We have given $0.3\overline{3}=\dfrac{1}{3}$ and $0.6\overline{6}=\dfrac{2}{3}$. Adding both will give $0.3\overline{3}+0.6\overline{6}=\dfrac{1}{3}+\dfrac{2}{3}$. Now simplify to get $0.9\overline{9}$. We get, $0.9\overline{9}=\dfrac{3}{3}=1$
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