Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.4 Positive and Negative Real Numbers - 1.4 Exercise Set - Page 36: 95

Answer

$5.5\overline{5}=\dfrac{50}{9}$

Work Step by Step

We have given $0.3\overline{3}=\dfrac{1}{3}$ and $0.6\overline{6}=\dfrac{2}{3}$. Divide $0.3\overline{3}=\dfrac{1}{3}$ by $3$ on both sides. We get, $0.1\overline{1}=\dfrac{1}{9}$ Now multiply by $5$ on both sides of $0.1\overline{1}=\dfrac{1}{9}$ We get, $0.5\overline{5}=\dfrac{5}{9}$ Now to move the decimal point to the right for once. Multiply by $10$ on both sides. We get, $5.5\overline{5}=\dfrac{50}{9}$
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